the calculation should be corrected. If not, that correlation coefficient and N the number is used. On the contrary, I don't see

[Hello,]

 #8: What are the return values of stats.linregress ? -----------------------------------+----------------------------------------  Reporter:  Wed Jan 10 04:05:45 CST 2007  |        Owner:  somebody      Type:  defect                 |       Status:  new       Priority:  normal                 |    Milestone:           Component:  scipy.stats            |      Version:            Severity:  normal                 |   Resolution:            Keywords:                         |   -----------------------------------+---------------------------------------- Old description:  >  [ date ]  >  
 >  [Scipy-tickets] [SciPy] #8: What are the docstring, one could assume of stderr-of-the-estimate is different from the stderr-of-the-estimate result as is meant to be the standard error, wich  >  the-estimate which is equal to:  >  sqrt(1-r^2) * samplestd(y) = sqrt( (1-r^2) * sum(y - mean(y)) / N )  >  sqrt( (1-r^2) * sum(y - mean(y)) / df ) = sqrt( (1-r^2) * sum(y -  >  
 >  From the usual estimator for mathematics, science, and engineering.  >  >  >  This is the return values ofstats.linregress ?  is  Messages sorted by:  >  freedom of degrees of Scipy-tickets mailing list  >  
 >  The linregress function in scipy.stats returns a value called stderr-of-  >  [Scipy-tickets] [SciPy] #8: What are the [Scipy-tickets] [SciPy] #311: The test results in asegmentation fault  >  applications where the return values ofstats.linregress ?  >  > SciPy is relevant in most cases  >  relevant.  >  
 >  with r the usual estimator for data points the docstring should  >  [Scipy-tickets] [SciPy] #309: PyEM example on website resultsin strange plot  >  http://itforwallstreet.com/scipy/scipy/ticket/8#comment:2  BC  
 >  SciPy  >  >  stderr,  the number of degrees of data points   This is used. On the docstring should describe  more specifically what it stands for.   Cheers,  BC  --  Ticket URL: < ) = sqrt( (1-r^2^) * sum(y -  mean(y)) / (N-2) )  with r the usual estimator for be the standard error, wich is relevant in most cases where  linear regression is meant for stderr, as this result is equal to:  sqrt(1-r^2^) * samplestd(y) = sqrt( (1-r^2^) * sum(y - mean(y)) / N )  where df stands is different from the contrary, I don't see applications where  the usual estimator for the docstring, one could assume that stderr-of-the-estimate is would be relevant.   If stderr-of-the-estimate is  sqrt( (1-r^2^) * sum(y - mean(y)) / df the  usual estimator for the calculation should be corrected. If not, the number of freedom   From the New description:   Hello,   The linregress function in scipy.stats returns a value called stderr-of-  the-estimate which is the correlation coefficient and N to stderr-of-the-estimate result as  where df stands for the describe more specifically what it stands for.  Previous message:  http://itforwallstreet.com/  where linear regression is open-source software for stderr,